Problema 1
Calculo de pH
pH= -log [H+]
4.3= -log [H+]
-4.3 = log [H+]
10x 10x
10 -4.3 = [H+]
= 5.01 x 10 -5
= .000050118 m eq. /dl
pH= -log [H+]
4.1= -log [H+]
-4.1 = log [H+]
10x 10x
10 -4.1 = [H+]
= 7.943 x 10 -5
Comparación:
7.943 x 10 -5 / 5.01 x 10 -5 = 1.58
* El pH 4.1 tiene casi 1.6 mas [H+] que el pH 4.3
Problema 2
Sustancia | pH | [H+] |
Sangre arterial | 7.4 | 3.9 X 10 -8 |
Sangre venosa | 7.35 | 4.46 X 10 -8 |
Orina | 4.5-8 | 3.16 X 10 -8 - 1 X 10 -8 |
HCl | 0.8 | 0.15 |
Sangre arterial
pH = 7.4
7.4= -log [H+]
7.4 = log [H+]
10x 10x
10 -7.4= [H+]
[H+] = 3.9 X 10 -8
HCl / sangre arterial = 0.15 / 3.9 X 10 -8
= 3.8 x 10 6
= el HCl tiene 3.8 x 10 6 mas [H+] que la sangre arterial
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